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edited May 23, 2011 at 21:37

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bash: array Array of string expanded to path?

supposeSuppose I have the following initialization of bash array:

my_array=(
    "/usr/bin"
    "/usr/lib/*.so"
)

ifIf I do iteration using :

for array_item in ${my_array[@]} 
do 
    ... 
done

thenThen the content of the my_array is expanded containing path to any files with .so extension in /usr/lib/ directories. but I just wanted the array contain two string which is "/usr/bin" and "/usr/lib/*.so".

howHow should I do that?

bash: array of string expanded to path?

suppose I have the following initialization of bash array

my_array=(
    "/usr/bin"
    "/usr/lib/*.so"
)

if I do iteration using :

for array_item in ${my_array[@]} 
do 
    ... 
done

then the content of the my_array is expanded containing path to any files with .so extension in /usr/lib/ directories. but I just wanted the array contain two string which is "/usr/bin" and "/usr/lib/*.so".

how should I do that?

Array of string expanded to path?

Suppose I have the following initialization of bash array:

my_array=(
    "/usr/bin"
    "/usr/lib/*.so"
)

If I do iteration using:

for array_item in ${my_array[@]} 
do 
    ... 
done

Then the content of the my_array is expanded containing path to any files with .so extension in /usr/lib/ directories. but I just wanted the array contain two string which is "/usr/bin" and "/usr/lib/*.so".

How should I do that?

Source Link

asked Sep 18, 2010 at 21:54

uray

bash: array of string expanded to path?

suppose I have the following initialization of bash array

my_array=(
    "/usr/bin"
    "/usr/lib/*.so"
)

if I do iteration using :

for array_item in ${my_array[@]} 
do 
    ... 
done

how should I do that?

bash array string