Suppose I have a script like this:

#!/bin/bash
printf '%q\n' "a b"

Executing the script prints:

b\ c

on the commandline.

Now, being in a directory which contains a file named a\ b I want to pass the output of my script to a command like ls:

$ ls $(./myscript)

The problem here is that b\ c is split to b\ and c, i.e. two arguments, and ls of course cannot find them. Is there some way to circumvent this? I thought escaping the space in the output would be enough.

Suppose I have a script like this:

#!/bin/bash
printf '%q\n' "b c"

Executing the script prints:

b\ c

on the commandline.

Now, being in a directory which contains a file named b c I want to pass the output of my script to a command like ls:

$ ls $(./myscript)

The problem here is that b c is split to b\ and c, i.e. two arguments, and ls of course cannot find them. Is there some way to circumvent this? I thought escaping the space in the output would be enough.

Suppose I have a script like this:

#!/bin/bash

printf '%q\n' "a b"

Executing the script prints

b\ c

on the commandline.

Now, being in a directory which contains a file named a\ b I want to pass the output of my script to a command like ls:

$ ls $(./myscript)

The problem here is that b\ c is split to b\ and c, i.e. two arguments, and ls of course cannot find them. Is there some way to circumvent this? I thought escaping the space in the output would be enough.

Suppose I have a script like this:

#!/bin/bash
printf '%q\n' "a b"

Executing the script prints:

b\ c

on the commandline.

Now, being in a directory which contains a file named a\ b I want to pass the output of my script to a command like ls:

$ ls $(./myscript)

The problem here is that b\ c is split to b\ and c, i.e. two arguments, and ls of course cannot find them. Is there some way to circumvent this? I thought escaping the space in the output would be enough.