How to find size of an object in Python?
In python, the usage of sys.getsizeof() can be done to find the storage size of a particular object that occupies some space in the memory. This function returns the size of the object in bytes. It takes at most two arguments i.e Object itself.
Note: Only the memory consumption directly attributed to the object is accounted for, not the memory consumption of objects it refers to.
Examples:
Input:
# Any Integer Value
sys.getsizeof(4)
Expected Output: 4 bytes (Size of integer is 4bytes)
Actual Output: 28 bytes
Here's how we can interpret the actual output. Have a look at the table below:
Type of Object | Actual Size | Notes |
|---|---|---|
int |
28 | NA |
str |
49 | +1 per additional character (49+total length of characters) |
tuple | 40 (Empty Tuple) | +8 per additional item in a tuple ( 40 + 8*total length of items ) |
list | 56 (Empty List) | +8 per additional item in a list ( 56 + 8*total length of items ) |
set |
216 | 0-4 take the size of 216. 5-19 take size 728. 20th will take 2264 and so on... |
dict |
232 | 0-5 takes a size of 232. 6-10 size will be 360. 11th will take 640 and so on... |
func def |
136 | No attributes and default arguments |
Example:
import sys
# Getting size using getsizeof() method and lately
# printing the same.
a = sys.getsizeof(12)
print(a)
b = sys.getsizeof('geeks')
print(b)
c = sys.getsizeof(('g', 'e', 'e', 'k', 's'))
print(c)
d = sys.getsizeof(['g', 'e', 'e', 'k', 's'])
print(d)
e = sys.getsizeof({1, 2, 3, 4})
print(e)
f = sys.getsizeof({1: 'a', 2: 'b', 3: 'c', 4: 'd'})
print(f)
Output:
