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逸扬/leetcode-hub-mysql

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逸扬 提交于 2022-05-01 21:45 +08:00 . 602-610-612-613-614-615-620-1068-1069-1070 (10)
# $602. 好友申请 II :谁有最多的好友
# https://leetcode-cn.com/problems/friend-requests-ii-who-has-the-most-friends/
# SQL架构
Create table If Not Exists RequestAccepted (requester_id int not null, accepter_id int null, accept_date date null);
Truncate table RequestAccepted;
insert into RequestAccepted (requester_id, accepter_id, accept_date) values ('1', '2', '2016/06/03');
insert into RequestAccepted (requester_id, accepter_id, accept_date) values ('1', '3', '2016/06/08');
insert into RequestAccepted (requester_id, accepter_id, accept_date) values ('2', '3', '2016/06/08');
insert into RequestAccepted (requester_id, accepter_id, accept_date) values ('3', '4', '2016/06/09');
# Write your MySQL query statement below
select
id,
count(*) as num
from
(
select
requester_id as id
from
RequestAccepted
union
all
select
accepter_id
from
RequestAccepted
) tmp
group by
id
order by
count(*) desc
limit
1;
# clean-up
drop table RequestAccepted;
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