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lc-1142.test 2.28 KB
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# $1142. 过去30天的用户活动 II
# https://leetcode-cn.com/problems/user-activity-for-the-past-30-days-ii/
# SQL架构
Create table If Not Exists Activity (user_id int, session_id int, activity_date date, activity_type ENUM('open_session', 'end_session', 'scroll_down', 'send_message'));
Truncate table Activity;
insert into Activity (user_id, session_id, activity_date, activity_type) values ('1', '1', '2019-07-20', 'open_session');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('1', '1', '2019-07-20', 'scroll_down');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('1', '1', '2019-07-20', 'end_session');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('2', '4', '2019-07-20', 'open_session');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('2', '4', '2019-07-21', 'send_message');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('2', '4', '2019-07-21', 'end_session');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('3', '2', '2019-07-21', 'open_session');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('3', '2', '2019-07-21', 'send_message');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('3', '2', '2019-07-21', 'end_session');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('3', '5', '2019-07-21', 'open_session');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('3', '5', '2019-07-21', 'scroll_down');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('3', '5', '2019-07-21', 'end_session');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('4', '3', '2019-06-25', 'open_session');
insert into Activity (user_id, session_id, activity_date, activity_type) values ('4', '3', '2019-06-25', 'end_session');
# Write your MySQL query statement below
select
ifnull(
round(
count(distinct session_id) / count(distinct user_id),
2
),
0
) as average_sessions_per_user
from
Activity
where
datediff('2019-07-27', activity_date) < 30;
# clean-up
drop table Activity;
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