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逸扬/leetcode-hub-mysql

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lc-1699.test 1.31 KB
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逸扬 提交于 2022-04-10 21:46 +08:00 . 1173-1193-1211-1251-1445-1571-1633-1699 (8)
# $1699. 两人之间的通话次数
# https://leetcode-cn.com/problems/number-of-calls-between-two-persons/
# SQL架构
Create table If Not Exists Calls (from_id int, to_id int, duration int);
Truncate table Calls;
insert into Calls (from_id, to_id, duration) values ('1', '2', '59');
insert into Calls (from_id, to_id, duration) values ('2', '1', '11');
insert into Calls (from_id, to_id, duration) values ('1', '3', '20');
insert into Calls (from_id, to_id, duration) values ('3', '4', '100');
insert into Calls (from_id, to_id, duration) values ('3', '4', '200');
insert into Calls (from_id, to_id, duration) values ('3', '4', '200');
insert into Calls (from_id, to_id, duration) values ('4', '3', '499');
# Write your MySQL query statement below
select
tmp.person1 as person1,
tmp.person2 as person2,
count(*) as call_count,
sum(duration) as total_duration
from
(
select
from_id as person1,
to_id as person2,
duration
from
Calls
where
from_id < to_id
union
all
select
to_id as person1,
from_id as person2,
duration
from
Calls
where
from_id > to_id
) tmp
group by
tmp.person1,
tmp.person2;
# clean-up
drop table Calls;
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