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逸扬/leetcode-hub-mysql

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lc-1821.test 957 Bytes
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# $1821. 寻找今年具有正收入的客户
# https://leetcode.cn/problems/find-customers-with-positive-revenue-this-year/
# SQL架构
Create table If Not Exists Customers (customer_id int, year int, revenue int);
Truncate table Customers;
insert into Customers (customer_id, year, revenue) values ('1', '2018', '50');
insert into Customers (customer_id, year, revenue) values ('1', '2021', '30');
insert into Customers (customer_id, year, revenue) values ('1', '2020', '70');
insert into Customers (customer_id, year, revenue) values ('2', '2021', '-50');
insert into Customers (customer_id, year, revenue) values ('3', '2018', '10');
insert into Customers (customer_id, year, revenue) values ('3', '2016', '50');
insert into Customers (customer_id, year, revenue) values ('4', '2021', '20');
# Write your MySQL query statement below
select
customer_id
from
Customers
where
year = 2021
and revenue > 0;
# clean-up
drop table Customers;
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