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lc-1875.test 1.13 KB
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# $1875. 将工资相同的雇员分组
# https://leetcode.cn/problems/group-employees-of-the-same-salary/
# SQL架构
Create table If Not Exists Employees (employee_id int, name varchar(30), salary int);
Truncate table Employees;
insert into Employees (employee_id, name, salary) values ('2', 'Meir', '3000');
insert into Employees (employee_id, name, salary) values ('3', 'Michael', '3000');
insert into Employees (employee_id, name, salary) values ('7', 'Addilyn', '7400');
insert into Employees (employee_id, name, salary) values ('8', 'Juan', '6100');
insert into Employees (employee_id, name, salary) values ('9', 'Kannon', '7400');
# Write your MySQL query statement below
select
employee_id,
name,
b.salary,
b.team_id
from
Employees e
inner join (
select
salary,
dense_rank() over (
order by
salary
) as team_id
from
Employees
group by
salary
having
count(distinct employee_id) > 1
) b on e.salary = b.salary
order by
b.team_id,
employee_id;
# clean-up
drop table Employees;
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