Ok so this seems like a pretty dumb question but PHP Is telling me I can't do this, or rather my IDE...
In the below example its telling me I can't use $this->somevar as the default value for the method.
ie...
class something {
public somevar = 'someval';
private function somefunc($default = $this->somevar) {
}
}
I'm afraid your IDE is correct. This is because "the default value must be a constant expression, not (for example) a variable, a class member or a function call." — Function arguments
You'll need to do something like this:
class something {
public $somevar = 'someval';
private function somefunc($default = null) {
if ($default === null) {
$default = $this->somevar;
}
}
}
This can also be written using the ternary operator:
$default = $default ?: $this->somevar;
public somevar = 'someval'; is missing the $ and should be public $somevar = 'someval'; I copied and pasted to just re-craft it and lost about 30 seconds flummoxed. Posted this here just in case another numbskull comes along!
"The default value [of a function argument] must be a constant expression, not (for example) a variable, a class member or a function call."
You could use my tiny library ValueResolver in this case, for example:
class something {
public somevar = 'someval';
private function somefunc($default = null) {
$default = ValueResolver::resolve($default, $this->somevar); // returns $this->somevar value if $default is empty
}
}
and don't forget to use namespace use LapaLabs\ValueResolver\Resolver\ValueResolver;
There are also ability to typecasting, for example if your variable's value should be integer, so use this:
$id = ValueResolver::toInteger('6 apples', 1); // returns 6
$id = ValueResolver::toInteger('There are no apples', 1); // returns 1 (used default value)
Check the docs for more examples
$default = $default ?: $this->somevar;?isset function in code