cannot parse String with Java Regex

Question

I have a string formatted as below:

source1.type1.8371-(12345)->source2.type3.3281-(38270)->source4.type2.903..

It's a path, the number in () is the weight for the edge, I tried to split it using java Pattern as following:

[a-zA-Z.0-9]+-{1}({1}\\d+){1}
[a-zA-Z_]+.[a-zA-Z_]+.(\\d)+-(\\d+)
[a-zA-Z.0-9]+-{1}({1}\\d+){1}-{1}>{1}

hopefully it split the string into fields like

source1.type1.8371-(12345)
source2.type3.3281-(38270)
..

but none of them work, it always return the whole string as the field.

i dont get it, what is expected result? and your string ends with ... ? — rcpayan
– rcpayan, Commented May 23, 2013 at 18:16

FDinoff · Accepted Answer · 2013-05-23 18:19:52Z

1

It looks like you just want String.split("->") (javadoc). This splits on the symbol -> and returns an array containing the parts between ->.

String str = "source1.type1.8371-(12345)->source2.type3.3281-(38270)->source4.type2.903..";
for(String s : str.split("->")){
    System.out.println(s);
}

Output

source1.type1.8371-(12345)
source2.type3.3281-(38270)
source4.type2.903..

answered May 23, 2013 at 18:19

FDinoff

31.6k5 gold badges80 silver badges99 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

aaronman · Accepted Answer · 2013-05-23 18:20:37Z

1

It seems to me like you want to split at the ->'s. So you could use something like str.split("->") If you were more specific about why you need this maybe we could understand why you were trying to use those complicated regexes

answered May 23, 2013 at 18:20

aaronman

18.8k8 gold badges65 silver badges81 bronze badges

Collectives™ on Stack Overflow

cannot parse String with Java Regex

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related