Javascript array reset not giving desired output

Question

I used the method described here:

to reset an array in my code.

My code is such

var check = new Array();
var i = 0;

if(some statements){
    check[i]=something;
    i=+1;
}

function reset(){
    check.length=0;
}

After executing of if statement, if I console.log(), the array is displayed as such

["abc","def","ghi"]. Then the reset function is called.

After that, the next time the array is used, it logs as follows:

[1: "abc", 2: "def", ...]

What can I do to make it reset to original empty array?

I think it's i+=1; too. I don't think you can have it round the other way. — Andy
– Andy, Commented Jan 15, 2014 at 14:24

BenM · Accepted Answer · 2014-01-15 14:25:23Z

5

You can simplify your whole code using:

var check = [];

if(some statements)
{
    check.push(something);
}

function reset()
{
    check = [];
}

It may be better to refactor your code though. check may be out of scope inside the function, so you should try:

var check = [];

if(some statements)
{
    check.push(something);
}

function reset()
{
    return [];
}

check = reset();

answered Jan 15, 2014 at 14:25

BenM

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4 Comments

newfurniturey Over a year ago

While check = [] will definitely clear the array, it does so by creating an entirely new array; if there are any references to the original one, this will break them...

j08691 Over a year ago

The problem seems to be that check.length = 0; is apparently not working for the OP (when it should), but you haven't explained why.

Newtt Over a year ago

Exactly. Nevertheless, I fixed it by resetting the variable i.

BenM Over a year ago

But you don't need to use the i variable at all?

user2575725 · Accepted Answer · 2014-01-15 15:17:29Z

0

Try this:

function reset() {
  check.splice(0, check.length);
}

answered Jan 15, 2014 at 15:17

user2575725

1 Comment

user2575725 Over a year ago

this will retain the same array, only the elements will be discared

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