How to access part of an array in ajax

Question

In my ajax, the PHP side contains an array with 3 values. I'd like to put these 3 values into separate input fields. How can I do this? How do I access the array sent from PHP?

My code so far:

PHP

    $total['tot1'] = $numwelds + $numconwelds + $mpcountrys ;
    $total['tot2'] = $numwelds + $numconwelds + $fortot2 ;
    $total['tot3'] = $numwelds + $numconwelds + $fortot2 / $fortot3; 
    $response = json_encode($total);
    header("Content-Type: application/json");  
    echo $response;
    exit;

Jquery

 jQuery(document).ready( function($) {
        (function($) {
        $(document).ready(function(){
           $('#formsubmit').click(function(){
          $.post(
          PT_Ajax.ajaxurl,
                {
               action : 'ajax-inputtitleSubmit',
               numberofwelds : $('input[name=numberofwelds]').val(),
               numberofconwelds : $('input[name=numberofconwelds]').val(),
               nextNonce : PT_Ajax.nextNonce
                },
          function( response ) {
              $("#totalone").val(response);
               $("#totaltwo").val(response);
                $("#totalthree").val(response);
                }
                );
              return false;
        }); 

        });
        })(jQuery);
        });

Your jQuery is oddly nested. You're already in a document.ready, and you open another document.ready inside an IIFE? You should get rid of jQuery(document).ready( function($) { (function($) {, everything before $(document).ready. — user229044
– user229044 ♦, Commented Mar 25, 2014 at 18:32
possible duplicate of Accessing the Object values inside an array — brandonscript
– brandonscript, Commented Mar 25, 2014 at 18:36

Sarfraz · Accepted Answer · 2014-03-25 18:32:54Z

0

You can use JSON.parse to convert json to object:

var obj = JSON.parse(response);
$("#totalone").val(obj.tot1);
$("#totaltwo").val(obj.tot2);
$("#totalthree").val(obj.tot3);

Or you can also use $.parseJSON() of jQuery.

answered Mar 25, 2014 at 18:32

Sarfraz

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Comments

Nunser · Accepted Answer · 2014-03-25 19:10:49Z

0

use like

$("#totalone").val(response["tot1"]);
$("#totaltwo").val(response["tot2"]);
$("#totalthree").val(response["tot3"]);

edited Mar 25, 2014 at 19:10

Nunser

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answered Mar 25, 2014 at 18:31

Anoop Joshi P

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