Get all values of a particular attribute from xml using python

Question

I need to get all values of a particular attribute. The tag name of that attribute might be different and the attribute might be at any level in the xml tree (root level / child level / etc.). Consider the following xml

<?xml version="1.0" encoding="utf-8"?>
    <college name ="xyz"/>
    <university>
        <college name = "abc1" id = "a"/>
        <college name = "abc2" id = "b"/>
        <sub-univ>
            <sub-univ-col name = "sfd"/>
        </sub-univ>
    </university>
    <school name = "asdf"/>enter code here

How do I get the value of "name" attribute from all the xml tags.? XML file which I has much more levels than the example stated above. Is there any way to get the values without parsing at every level?

roippi · Accepted Answer · 2014-05-14 05:25:09Z

1

Straightforward in any parser that supports XPath. For example, lxml:

doc = lxml.etree.fromstring(that_xml_you_gave)

doc.xpath('//@name')
Out[208]: ['xyz', 'abc1', 'abc2', 'sfd', 'asdf']

answered May 14, 2014 at 5:25

roippi

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senshin · Accepted Answer · 2014-05-14 05:28:03Z

If you use Beautiful Soup, this becomes pretty easy:

from bs4 import BeautifulSoup

xml = '''
<?xml version="1.0" encoding="utf-8"?>
    <college name ="xyz"/>
    <university>
        <college name = "abc1" id = "a"/>
        <college name = "abc2" id = "b"/>
        <sub-univ>
            <sub-univ-col name = "sfd"/>
        </sub-univ>
    </university>
    <school name = "asdf"/>
'''

soup = BeautifulSoup(xml)
names = [tag.get('name') for tag in soup.find_all()]
print(names)

Result:

['xyz', None, 'abc1', 'abc2', None, 'sfd', 'asdf']

Note that we use tag.get(...) because some of the tags don't have a name attribute. Alternatively, you could instead do:

names = [tag['name'] for tag in soup.find_all() if tag.has_attr('name')]

With result:

['xyz', 'abc1', 'abc2', 'sfd', 'asdf']

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