Access php variable in html

Question

I am using the below php code:

<?php 
$str = time().'_'.$_FILES["file1"]["name"];
$fileName = $_FILES["file1"]["name"]; 
$fileTmpLoc = $_FILES["file1"]["tmp_name"]; 
$fileType = $_FILES["file1"]["type"]; 
$fileSize = $_FILES["file1"]["size"]; 
$fileErrorMsg = $_FILES["file1"]["error"]; 

if (!$fileTmpLoc) { 
    echo 'ERROR: Please browse for a file before clicking the upload button.'; 
    exit(); 
} 

if(move_uploaded_file($fileTmpLoc, "upload/" . $str)){ 
    echo "$fileName upload is complete"; 
} else { 
    echo 'move_uploaded_file function failed'; 
}
?>

to upload a file on a server. I am altering the filename and keeping it in $str. My question is:

When the upload is completed I want to be able in my html file to print a message like

You uploaded <?php echo $str; ?>

How can I do that? How can I access $str ? Shall I use sessions? Any hint? Thank you a lot in advance...

Remove space between <? php

Raptor
– Raptor

2014-10-11 03:22:40 +00:00
Commented Oct 11, 2014 at 3:22 — Raptor
– Raptor, Commented Oct 11, 2014 at 3:22
Thanks Raptor, I removed it.

pebox11
– pebox11

2014-10-11 12:25:44 +00:00
Commented Oct 11, 2014 at 12:25 — pebox11
– pebox11, Commented Oct 11, 2014 at 12:25

meda · Accepted Answer · 2014-10-11 02:33:26Z

3

Simply store the return value of move_uploaded_file

$is_uploaded = move_uploaded_file($fileTmpLoc, "upload/" . $str);
if($is_uploaded ){ 
   echo "$fileName upload is complete"; 
} else { 
   echo "move_uploaded_file function failed"; 
}

in HTML

if($is_uploaded ){ 
   echo "<p>You uploaded ".$str."<p>"; 
}

edited Oct 11, 2014 at 2:33

answered Oct 11, 2014 at 2:09

meda

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9 Comments

pebox11 Over a year ago

When I add your $is_uploaded... code in my php, the upload breaks and does not work.

meda Over a year ago

oh sorry i forgot semi colon move_uploaded_file($fileTmpLoc, "upload/" . $str);

pebox11 Over a year ago

Now the upload works (I am sorry too that I didn't notice the absence of semi colon), however now the if part does not seem to work. For example a paste in my html of <?php if($is_uploaded ){ echo "<p>You uploaded ".$str."<p>"; } ?> gives me the message: "You uploaded ".$str." "; } ?> " .

meda Over a year ago

What do you mean i dont understand? Can u show ur html

meda Over a year ago

Let us continue this discussion in chat.

|

Alleo Indong · Accepted Answer · 2014-10-11 03:25:19Z

0

Local php variables will get deleted or "flushed" when the web browser REFRESHED. To solve this,

you must use AJAX and return a JSON response to your html file for the successful upload

or

Store the success or error message on a Session then unset that session after you showed it for example

<?php
   @session_start();

    //file upload code
    //if success
        $_SESSION['message'] = 'File successfully uploaded';
    //else
        $_SESSION['message'] = 'File upload error';
?>

then into your HTML

     <?php @session_start() ?>

     <body>
         <?php if(isset($_SESSION['message']): ?>
                <p><?php echo $_SESSION['message']; ?></p>
                <?php unset($_SESSION['message']) ?>
         <?php endif; ?>
     </body>

answered Oct 11, 2014 at 3:25

Alleo Indong

3273 silver badges13 bronze badges

5 Comments

pebox11 Over a year ago

I used your direction but with no luck... I am pretty much convinced though that I should use sessions and ajax...

Alleo Indong Over a year ago

I just showed you how the structure, not the full code, you have to create the full code yourself

pebox11 Over a year ago

I did... I will try again... Thanks!

Alleo Indong Over a year ago

Good luck, if you can't see a message it means the $_SESSION['message'] is empty

Alleo Indong Over a year ago

have fun experimenting

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