2

My JSON looks like this

{"rows":[
    {"key":["zeit.de"],"value":98},
    {"key":["google.com"],"value":49},
    {"key":["spiegel.de"],"value":20},
    {"key":["spiegel.de"],"value":12},
    {"key":["spiegel.de"],"value":20},
    {"key":["spiegel.de"],"value":12},
    {"key":["netmng.com"],"value":49},
    {"key":["zeit.de"],"value":300}
]}

and I am looking for a solution to merge all the same keys and add the values of the merged keys together to get something looking like this.

{"rows":[
    {"key":["zeit.de"],"value":398},
    {"key":["google.com"],"value":49},
    {"key":["spiegel.de"],"value":54},
    {"key":["netmng.com"],"value":49}
]}

Thanks for answersing.

1
  • Loop over the object and load the items into a new object by key using += to add the new value to the previous one. Commented Jun 14, 2015 at 18:46

5 Answers 5

4

var json = '{"rows":[{"key":["zeit.de"],"value":98},{"key":["google.com"],"value":49},{"key":["spiegel.de"],"value":20},{"key":["spiegel.de"],"value":12},{"key":["spiegel.de"],"value":20},{"key":["spiegel.de"],"value":12},{"key":["netmng.com"],"value":49},{"key":["zeit.de"],"value":300}]}';
var obj = JSON.parse(json);

var newObj = {};
for(i in obj['rows']){
 var item = obj['rows'][i];
    if(newObj[item.key[0]] === undefined){
        newObj[item.key[0]] = 0;
    }
    newObj[item.key[0]] += item.value;
}

var result = {};
result.rows = [];
for(i in newObj){
    result.rows.push({'key':i,'value':newObj[i]});
}
console.log(result);

https://jsfiddle.net/s8rp84qc/

Sign up to request clarification or add additional context in comments.

Comments

3

Here's an alternate solution using ECMA-Script Array functions forEach, some and filter:

var data = {
  "rows": [{
    "key": ["zeit.de"],
    "value": 98
  }, {
    "key": ["google.com"],
    "value": 49
  }, {
    "key": ["spiegel.de"],
    "value": 20
  }, {
    "key": ["spiegel.de"],
    "value": 12
  }, {
    "key": ["spiegel.de"],
    "value": 20
  }, {
    "key": ["spiegel.de"],
    "value": 12
  }, {
    "key": ["netmng.com"],
    "value": 49
  }, {
    "key": ["zeit.de"],
    "value": 300
  }]
};

var merged = {
  rows: []
};

data.rows.forEach(function(sourceRow) {
  debugger;
  if(!merged.rows.some(function(row) { return row.key[0] == sourceRow.key[0]; })) {
    merged.rows.push({ key: [sourceRow.key[0]], value: sourceRow.value });
  } else {
    var targetRow = merged.rows.filter(function(targetRow) { return targetRow.key[0] == sourceRow.key[0] })[0];
    
    targetRow.value += sourceRow.value;
  }
});

document.getElementById("result").textContent = JSON.stringify(merged);
<div id="result"></div>

Comments

0

You can try something like this:

var newData = {rows: []},
    index;

for (var i = 0; i < data.rows.length;i++){
    index = newDataContains(data.rows[i].key);
    if (index == -1){
        newData.rows.push({key: data.rows[i].key, value: data.rows[i].value});
    } else {
        newData.rows[index].value += data.rows[i].value;
    }
}

function newDataContains(key){
    for (var i=0; i < newData.rows.length; i++){
        if (JSON.stringify(newData.rows[i].key) == JSON.stringify(key)) {
            return i;
            break;
        }
    }
    return -1;
}

jsfiddle: https://jsfiddle.net/9p81g5j6/

Comments

0

you can use lodash

let result = [{'a': 3, 'b': 2}, {'a': 4, 'c': 1}, {'a': 4, 'c': 1}];
let m = _.reduce((_.uniq(_.flattenDeep(_.map(result, i => _.keys(i))))), function (s, v) {
    s[v] = _.sumBy(result, function (o) {
        return o[v];
    });
    return s
}, {});

console.log(m); // { a: 11, b: 2, c: 2 }

Comments

0

JSON look like below: 2 scenario Url is common When pass the role -id

  1. role- id/name has admin:

    [{"Key":"value1"},{"key":"value2"},{"key":"value3"}]
    
  2. role- id/name has Tester

    [{"Key":"value1"},{"key":"value3"}]
    

no key:value2 is there for Tester

For example:

Global variable string a, b;

wants to take all of the values from the key-value Pair if it has value2 and value3 from the JSON

i.e.: admin go for a="both"

check Tester if it has only value3 then b="single"

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.