Java: Convert encoded characters to regular string

Question

I have a string like this in Java: "\xd0\xb5\xd0\xbd\xd0\xb4\xd0\xbf\xd0\xbe\xd0\xb9\xd0\xbd\xd1\x82"

How can I convert it to a human readable equivalent?

Note: actually it is GWT and this string is coming from python as part of a JSON data. The JSONParser transforms it to something that is totally irrelevant, so I want to be able to convert the string prior to parsing.

The expected, so called by me "human readable", should be "ендойнт" (https://mothereff.in/utf-8#%D0%B5%D0%BD%D0%B4%D0%BF%D0%BE%D0%B9%D0%BD%D1%82)

I am a human, I can read the string you have posted, also you have not posted how they were encoded??? — We are Borg
– We are Borg, Commented Jul 9, 2015 at 15:40
You link to some site that can decode it (using utf8.js) so the answer to your question seems to be: use utf8.js. That said, \xHH is not valid in a JSON string, so you probably have a bug in your Python serializer. Also, maybe try new String(str.getBytes("ISO-8859-1"), "UTF-8"). — Thomas Broyer
– Thomas Broyer, Commented Jul 9, 2015 at 16:12

Community · Accepted Answer · 2017-05-23 12:14:04Z

0

Assuming that the pattern is a repetition of characters in the form of "\x00", where 00 can be any number or letter in [a-fA-F], you can convert it with something like this:

String values = "\\xd0\\xb5\\xd0\\xbd\\xd0\\xb4\\xd0\\xbf\\xd0\\xbe\\xd0\\xb9\\xd0\\xbd\\xd1\\x82";
for (String val: values.split("\\\\x")) {
        if (val.length() > 0 ) System.err.print((char) Integer.parseInt(val, 16));
}

Note that the if condition is due to the first delimiter: see How to prevent java.lang.String.split() from creating a leading empty string?

edited May 23, 2017 at 12:14

CommunityBot

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answered Jul 9, 2015 at 15:55

Andrea Iacono

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Comments

triForce420 · Accepted Answer · 2015-07-09 16:46:33Z

I don't know if it's just my console or it's not working, but you may try this code:

import java.io.UnsupportedEncodingException;

import javax.xml.bind.DatatypeConverter;

public class Utf8Decoder {

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        String url = "\\xd0\\xb5\\xd0\\xbd\\xd0\\xb4\\xd0\\xbf\\xd0\\xbe\\xd0\\xb9\\xd0\\xbd\\xd1\\x82";
        url= url.replaceAll("\\\\x", ""); //remove the \x on the string... 
        //it is now hex so let's parse it
        //convert to human readable text
        String result="";
        try {
            byte[] bytes= DatatypeConverter.parseHexBinary(url);
            result = new String(bytes, "UTF-8");
        } catch (UnsupportedEncodingException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
            System.out.print("decoded value:"+result);
    }

}

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