Execute a python script using Popen with shell=False

Question

I would like to know if it's possible to execute this command

cmd = "gnome-terminal -e 'python /path/to/file.py'"

p = subprocess.Popen(cmd,shell=True)

but with shell=False

I tried to run this command

p = subprocess.Popen(["gnome-terminal","-e","python","/path/to/file.py"],shell = False)

but it's not working:

Thank you!

It will just open python, but it will not execute the python script (file.py) @RahulKP — Elie khalifeh
– Elie khalifeh, Commented Jun 10, 2016 at 15:55
Are you trying to execute python file from another python file ? — Rahul K P
– Rahul K P, Commented Jun 10, 2016 at 15:57
@RahulKP: it doesn't work: read about the difference between -e and -x options. — jfs
– jfs, Commented Jun 12, 2016 at 15:34

Ignacio Vazquez-Abrams · Accepted Answer · 2016-06-10 15:57:26Z

2

As it is you're passing the command to gnome-terminal, not python.

p = subprocess.Popen(["gnome-terminal","-e","python /path/to/file.py"],shell = False)

answered Jun 10, 2016 at 15:57

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3 Comments

Don't know why I didn't try this, but THANK YOU! :)

@Eliekhalifeh: if you want to pass separate command-line arguments as the command, use -x instead of -e in your code.

@J.F.Sebastian It worked using the above answer, but thank you, I'll keep this in mind!