get index in multidimensional array in javascript

Question

This question is follow up for, Get the index of a multidimensional array with the value of a given string in javascript

I tried this answer,

var    a1 = [["present",["John","Josh","Jay"]],["absent",["May","Mary","Mary Jane"]]],
   a2 = [["J",["John","Josh","Jay"]],["M",["May","Mary","Mary Jane"]],["S",["Sally","Sam","Sammy Davis"]]],
getStatus = (a,n) => a.find(e => e[1].indexOf(n) !== -1)[0],
getIndex = (a,n) => a.findIndex(e => e[1].indexOf(n) !== -1);

console.log(getStatus(a1,"Mary"));
console.log(getIndex(a2,"Sammy Davis"));

This is working, but there are issues. What if the given string is not in the array? how to handle that? How to get all the indexes if there are more than one index that have a value of the given string?

For example, In the a1,

var a1 = ["present",["John","Josh","Jay"]],["absent",["May","Josh","Mary Jane"]]]

How to get 0,1? using getIndex()?

Not an answer, but I don't understand why you are using a multidimensional array for a1 instead of an object, seems like there is no gain. { present: ['John, 'Josh'], absent: ['May', 'Mary Jane']} would be easier to work with — Rob M.
– Rob M., Commented Oct 18, 2016 at 18:38
JavaScript doesn't have multidimensional arrays, just arrays-of-arrays and such. — mu is too short
– mu is too short, Commented Oct 18, 2016 at 18:40

Redu · Accepted Answer · 2016-10-18 20:57:38Z

0

I have to agree with @Rob M.'s comment yet still you might do as follows;

var    a1 = [["present",["John","Josh","Jay"]],["absent",["May","Mary","Mary Jane"]]],
       a2 = [["J",["John","Josh","Jay"]],["M",["May","Mary","Mary Jane"]],["S",["Sally","Sam","Sammy Davis"]]],
getStatus = (a,n) => a.find(e => e[1].indexOf(n) !== -1)[0],
 getIndex = (a,n) => { var x = -1;
                       return [a.findIndex(e => (x = e[1].indexOf(n), x !== -1)),x];
                     };
console.log(getIndex(a2,"May"));
console.log(getIndex(a2,"Sammy Davis"));
console.log(getIndex(a2,"Daniel"));

edited Oct 18, 2016 at 20:57

answered Oct 18, 2016 at 20:52

Redu

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