concat string in shell command line

Question

I need some help to finalize a command line. I need to get a property name "server.port" in some files "applications.properties", and then make a curl on "myIp:server.port/health"

I get properties value with the following line, and the curl command get the param, but i can't add IP before and /health after.

Could you help me to finalize this command line ?

cat ms-something-*/application.properties | grep server.port | awk '{print $3}' | xargs curl

So without the last element "xargs curl", the line return a list of port number. but i need to add the ip (for example 8.8.8.8) and /health, to call curl on "8.8.8.8:server.port/health"

Can you post the contents of application.properties file on which grep on server port? — Inian
– Inian, Commented Nov 16, 2016 at 10:10

MarcoS · Accepted Answer · 2016-11-16 10:12:15Z

4

cat ms-something-*/application.properties | grep server.port | awk '{print "8.8.8.8:"$3"/health"}' | xargs curl

should work for you, if I correctly understand your question...

edited Nov 16, 2016 at 10:12

answered Nov 16, 2016 at 10:08

MarcoS

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2 Comments

Inian Over a year ago

If I understand right, you are missing a : right after the IP and just before port value.

M.Be Over a year ago

That's it ! i was trying to echo something but i don't think about concat inside the print... It work fine. thanks for your help.

Moritz Sauter · Accepted Answer · 2016-11-16 10:12:11Z

1

You can achieve this also with a for loop.

for port in $(cat ms-something-*/application.properties | grep server.port | awk '{print $3}') ; do 
    curl "8.8.8.8:${port}/health"
done

answered Nov 16, 2016 at 10:12

Moritz Sauter

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