Python pattern matching regex

Question

value=['0.203973Noerror(0)', '0.237207Noerror(0)','-1Timedout(-2)']

pattern=re.compile("\D\\(\d|[-]\d\\)")

temp=[]

for i in range(0,len(value)):
    err=pattern.match(value[i])
    if err:
        temp=value[i]
print(temp)

I want parsing the value:

[Noerror(0),Noerror(0),Timedout(-2)]

But when I'm processing code, the result is:

[0.203973Noerror(0),0.237207Noerror(0)',-1Timedout(-2)]

I don't know why this result comes out... please advice to me.

Change match to search, as match always starts matching from the beginning of the string. — DYZ
– DYZ, Commented Apr 21, 2017 at 7:29
You may use re.search(r'[a-zA-Z]+$-?[0-9]+$$', value[i]).group() — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Apr 21, 2017 at 7:30
The following regular expression should work, too: re.search(r'[^(0-9]+$[^)]+?$',value[i]).group(). — DYZ
– DYZ, Commented Apr 21, 2017 at 7:38

Community · Accepted Answer · 2017-05-23 12:17:42Z

2

Based on DYZ answer:

import re


results = []
pattern = re.compile(r'([a-z]+\([0-9-]+\))', flags=re.I)
value = ['0.203973Noerror(0)', '0.237207Noerror(0)','-1Timedout(-2)']

for v in value:
    match = pattern.search(v)
    if match:
        results.append(match.group(1))

print results

edited May 23, 2017 at 12:17

CommunityBot

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answered Apr 21, 2017 at 7:45

jpnkls

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Comments

Kind Stranger · Accepted Answer · 2017-04-21 07:57:42Z

1

For bonus points, you can split the numbers from the errors into tuples:

import re

value=['0.203973Noerror(0)', '0.237207Noerror(0)','-1Timedout(-2)']
temp=[]

for val in value:
    err = re.match(r'^([0-9.-]+)(.+)$', val)
    if err:
        temp.append(err.groups())

print temp

Gives the following:

[('0.203973', 'Noerror(0)'), ('0.237207', 'Noerror(0)'), ('-1', 'Timedout(-2)')]

If you just want the errors, then:

temp2 = [ t[1] for t in temp ]
print temp2

Gives:

['Noerror(0)', 'Noerror(0)', 'Timedout(-2)']

answered Apr 21, 2017 at 7:57

Kind Stranger

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2 Comments

user5083592 Over a year ago

I have one more question, if the value is as below: value=['0.203973 No error (0)', '0.237207 No error (0)','-1 Timed out (-2)'] Can I apply to same regex rule on the code?

Kind Stranger Over a year ago

Slight amendment - add \s* between the groups: re.match(r'^([0-9.-]+)\s*(.+)$', val) gives: [('0.203973', 'Noerror (0)'), ('0.237207', 'Noerror (0)'), ('-1', 'Timedout (-2)')]

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