How to use variable in curl command in Linux bash shell script to send post request with file?

Question

eg. I can execute below command in terminal successfully:

curl -sX POST -F 'file=@/tmp/test.tgz' -F 'fileName=test.tgz' http://localhost:8080/upload

However, if I replace the file path str "/tmp/test.tgz" with a variable in a bash shell script, then it wouldn't work, could you please help to tell me how to resolve it?

curl -sX POST -F 'file=@$myfile' -F 'fileName=test.tgz' http://localhost:8080/upload

Vadim Ponomarev · Accepted Answer · 2017-06-24 06:56:07Z

1

Use " instead of ' if you want variable expansion

answered Jun 24, 2017 at 6:56

Vadim Ponomarev

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Stanal Wellia · Accepted Answer · 2018-11-10 20:23:39Z

0

ff="'file=$myfile'"
fname="'fileName=test.tgz'"
eval curl -sX POST -F $ff $fname http://localhost:8080/upload

answered Nov 10, 2018 at 20:23

Stanal Wellia

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