float' object cannot be interpreted as an integer

Question

I have code:

  a = int(input("Type a integer："))
    temp = []
    while a != 1:
  --->   for i in range(2, a):
            if a % i == 0:
                temp.append(i)
                a = a / i
                break
    print(temp)

I typed 60 and then it gives the error: TypeError: 'float' object cannot be interpreted as an integer.

However, I checked:

a = int(input("Type a integer"))
type(a)

It shows type of a is int.

If so, where is the float type comes from?

You're dividing! a will become a float if it's not divisible by i (creating fractional parts). — Andrew Li
– Andrew Li, Commented Aug 10, 2017 at 18:48

evanklicker · Accepted Answer · 2017-08-10 18:54:49Z

4

When you divide a by i, it becomes a decimal number after so many iterations. If you started with 60, then the operations would follow like this:

a = 60 / 2     (=30)
a = 30 / 3     (=10)
a = 10 / 4     (=2.5)

Now, we can see that a is trying to be a float when you told it to be an integer.

answered Aug 10, 2017 at 18:54

evanklicker

1216 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

ZAhmed · Accepted Answer · 2017-08-10 18:51:46Z

1

When you divide it by a number , it become a float , you can return it to integer by :

a = int(a)

after

a = a/i

Or :

 a = a//i

answered Aug 10, 2017 at 18:51

ZAhmed

1,2908 silver badges15 bronze badges

Comments

Martin the noob · Accepted Answer · 2017-08-10 18:54:24Z

1

The float comes from using float division a/i. To get an int use integer division a//i

answered Aug 10, 2017 at 18:54

Martin the noob

112 bronze badges

Collectives™ on Stack Overflow

float' object cannot be interpreted as an integer

3 Answers 3

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related