bash script runs but does not display values

Question

my script runs without any errors but does not display the variable values. The output of the screen is two spaced blank lines.

#! /bin/bash

set v1=25
set v2 [format "%c" $v1]

echo "$v1"
echo "$v2"

chepner · Accepted Answer · 2017-10-11 13:28:58Z

2

set isn't used to set the value of a regular variable; it is used to set the positional parameters.

$ set v1=25
$ echo "$1"
v1=25
$ v1=25
$ echo "$v1"
25

Based on [format "%c" $v1], you appear to be writing a hybrid of Tcl and shell.Abash` equivalent would be

v2=$(printf "\x$(printf '%x' "$v1"))

edited Oct 11, 2017 at 13:28

answered Oct 11, 2017 at 13:09

chepner

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2 Comments

aero Over a year ago

Hi chepner, thanks for the input, would it be possible to show a working example of the format command?

chepner Over a year ago

bash doesn't really have a simple equivalent to convert an integer into the ASCII character it represents. You may be better off figuring out if you really need to do this.

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