Getting incorrect output from HTML form using $_POST method

Question

I was having trouble with getting my login form to redirect to user home page since last night, after one successful attempt. After filling the form, I would press submit but I remained on the same page, except the form would be cleared. So i decided to echo my inputs using the $_POST method, and after resubmitting the form, I saw that the page displayed 1 for both the entries. What is wrong in my code?

<!DOCTYPE html>

<?php require_once("../Includes/Session.php"); ?>
<?php require_once("../Includes/DB_Connection.php"); ?>
<?php require_once("../Includes/Functions.php"); ?>
<?php require_once("../Includes/Validation_Functions.php"); ?>

<head> 

<title> eTransport: Login</title>

<link rel="stylesheet" type="text/css" href="Login_Style.css">
</head>

<html> 
<body>
<div class="div1">
    <h1 class="title"> Online eTransport Service (Fiji) </h1>

    <div>
    <form action="Login.php" method="POST">
        eTransport_ID: <input type="text" name="eTransport_ID"><br>
        Password: <input type="password" name="Password"><br>
        <input type="submit" name="Submit" value="submit"><br>
        <?php echo isset($_POST['eTransport_ID']); ?><br>
        <?php echo isset($_POST['Password']); ?>
    </form>
    </div>
</div>
</body>
</html>

<?php

$id = isset($_POST['eTransport_ID']);
$password = isset($_POST['Password']);

$checked_id= mysql_prep($id);

$query = "SELECT eTransport_ID ,Password FROM etrans_id_details";

$login_set = mysqli_query($conn, $query);


while ($row = mysqli_fetch_assoc($login_set)){
    if ($checked_id == $row["eTransport_ID"] AND $password == $row["Password"]){
        redirect_to("Home.php");
    }
}

?>

The Output for my Code with $_POST:

You're storing the result of isset in $id and $password -- not the actual ID and password — j08691
– j08691, Commented Nov 16, 2017 at 2:23
it's displaying 1 because that you're using isset(). 1 = true in that sense. The variables are set. — Robert Wade
– Robert Wade, Commented Nov 16, 2017 at 2:23
I only added isset() since the browser gave 2 errors under the form as undefined index. how do I remove that? — Curious_guy1111
– Curious_guy1111, Commented Nov 16, 2017 at 2:31

Forbs · Accepted Answer · 2017-11-16 02:25:13Z

1

Here's the long answer. Replace $id = isset($_POST['eTransport_ID']); $password = isset($_POST['Password']);

with

$id = $_POST['eTransport_ID']; $password = $_POST['Password']; and add code to test if it is set.

answered Nov 16, 2017 at 2:25

Forbs

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2 Comments

Curious_guy1111 Over a year ago

Thanks, this worked, but upon reloading the Login page, it displays 2 errors saying undefined index. How do I remmove that?

Forbs Over a year ago

you need to put test to see if the variable is set so if ($id == '') die(0); and one for the other.

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