search contains string in array python

Question

I have a string like this search = 'hello' and I need check all array to see if any contains hello.
For example:

"hello" == "123hello123" | true
"hello" == "aasdasdasd123hello123" | true
"hello" == "123123hello" | true

I need something like search for my code

list_all_files_in_google_drive - it my all file name array

filename - name file, which need to check if exist in google drive or not

if not any(file['title'] == filename for file in list_all_files_in_google_drive):
   print('file not exist')

my code doesn't work because it works like this:

"hello" == "123hello123" | false
"hello" == "aasdasdasd123hello123" | false
"hello" == "123123hello" | false
"hello" == "hello" | true

and I need it to work like this:

"hello" == "123hello123" | true
"hello" == "aasdasdasd123hello123" | true
"hello" == "123123hello" | true
"hello" == "hello" | true

UPD:

I checked operator in and it does not output true

filename = 'hello'
list = ['123hello123', 'aasdasdasd123hello123', '123123hello']
if filename in list:
    print('true')

But you've replaced the whole loop with in. That's not what Rakesh told you to do. — Daniel Roseman
– Daniel Roseman, Commented Jan 12, 2018 at 6:59

RoadRunner · Accepted Answer · 2018-01-12 07:23:21Z

7

Just go through each string in the list with a simple loop, and check if 'hello' exists with the pythons membership in operator:

lst = ['123hello123', 'aasdasdasd123hello123', '123123hello']

for x in lst:
    if 'hello' in x:
        print('true')

Which outputs:

true
true
true

Or if you want to check all() the strings in lst at once:

if all('hello' in x for x in lst):
    print('true')

Or if you want to check if any() of the strings in lst at once:

if any('hello' in x for x in lst):
    print('true')

Both of which will output:

true

Note: Using list as a variable name as shown in your question is not a good idea here, as it shadows the builtin function list(). Also returning a boolean True or False here is fine, not need to return a string form of these.

edited Jan 12, 2018 at 7:23

answered Jan 12, 2018 at 7:01

RoadRunner

26.4k6 gold badges46 silver badges77 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Poiz Over a year ago

Why not for l in lst: if 'hello' in l: The Variable filename seems a little redundant....

r1299597 Over a year ago

@RoadRunner this example work perfetly, i use if any('hello' in x for x in lst): but mayby you know why this is false search_word = Taxi Stockholm Kostnad för resa 545 kr.pdf, and list contains [email protected]_Taxi Stockholm Kostnad för resa 545 kr.pdf why it output false?

Poiz · Accepted Answer · 2018-01-12 06:58:50Z

6

Replace '==' with 'in'

"hello" in "123hello123"            # RETURNS True
"hello" in "aasdasdasd123hello123"  # RETURNS True
"hello" in "123123hello"            # RETURNS True
"hello" in "hello"                  # RETURNS True

edited Jan 12, 2018 at 6:58

Poiz

7,5872 gold badges17 silver badges17 bronze badges

answered Jan 12, 2018 at 6:43

Rakesh

82.9k17 gold badges86 silver badges122 bronze badges

3 Comments

r1299597 Over a year ago

thks for answered, but i try you example and it not work, please see https://repl.it/repls/MintcreamDarkslategreyAustrianpinscher

Rakesh Over a year ago

Sorry I am unable to open the link you provided. Can you post what you tried in the comments?

Rakesh Over a year ago

if not any(file['title'] in filename for file in list_all_files_in_google_drive): print('file not exist') this is how to use 'in'

Vikas Periyadath · Accepted Answer · 2018-01-12 07:00:27Z

1

try this one dude :

filename = 'hello'
list = ['123hello123', 'aasdasdasd123hello123', '123123hello']
if (filename.find(file) for file in list):
      print('true')

answered Jan 12, 2018 at 7:00

Vikas Periyadath

3,1961 gold badge25 silver badges35 bronze badges

2 Comments

r1299597 Over a year ago

filename = '555' list = ['123hello123', 'aasdasdasd123hello123', '123123hello'] if (filename.find(file) for file in list):     print('true') else:     print('false')

it always output true

Vikas Periyadath Over a year ago

then change filename.find(file) to filename in file and try

Mahesh Karia · Accepted Answer · 2018-01-12 07:29:06Z

You can use list comprehensions as shown below:

filename = 'hello'
my_list = ['123hello123', 'aasdasdasd123hello123', '123123hello']

print all([True if filename in _ else False for _ in my_list])

filename = 'hello'
my_list = ['123hello123', 'aasdasdasd123hello123', '123123helo']

print all([True if filename in _ else False for _ in my_list])

output:

True
False

Another solution is to have a own function as follows:

def check_filename(filename_string, input_list):
    result = 'true'
    for _ in input_list:
        if filename_string not in _:
            result = 'false'
            break
    return result

filename = 'hello'
my_list = ['123hello123', 'aasdasdasd123hello123', '123123hello']

print(check_filename(filename_string=filename, input_list=my_list))

filename = 'hello'
my_list = ['123hello123', 'aasdasdasd123ho123', '123123hello']

print(check_filename(filename_string=filename, input_list=my_list))

output:

true
false

user9158931 · Accepted Answer · 2018-01-12 14:57:57Z

0

'in' operator is good solution , You can also try regex :

import re
pattern=r'hello'
lst = ['123hello123', 'aasdasdasd123hello123', '123123hello','nothing']
for i in lst:
    if re.search(pattern,i):
        print("string : {} result : {} ".format(i,True))
    else:
        print("string : {} result : {} ".format(i,False))

output:

string : 123hello123 result : True 
string : aasdasdasd123hello123 result : True 
string : 123123hello result : True 
string : nothing result : False

answered Jan 12, 2018 at 14:57

user9158931

Collectives™ on Stack Overflow

search contains string in array python

5 Answers 5

2 Comments

3 Comments

2 Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

5 Answers 5

2 Comments

3 Comments

2 Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related