\n54766392632990,178.32.243.13,wfsdsfsdfs23432,\n54766393632990,178.32.243.13,
Above u can see example of string which I want to parse.. I want to get array if numbers which exist between (\n....,178.32.243.13) .. In this example it will be smth like :
[54766392632990,54766393632990] - how to make it
Please run this script it full file your requirement
var ss = "\n54766392632990,178.32.243.13,wfsdsfsdfs23432,\n54766393632990,178.32.243.13,"
var ddd = ss.split(",")
console.log(ddd)
var dfd = []
ddd.forEach(function(res){
if(res.startsWith("\n"))
{
dfd.push(res.replace("\n",""))
}
})
console.log(dfd)
Result [ '54766392632990', '54766393632990' ]
"\n54766392632990,178.32.243.13,wfsdsfsdfs23432,\n54766393632990,178.32.243.13,"
.split("\n")
.filter((n)=> n!== "")
.map(n=> parseInt(n.split(",")[0]))
You can do something like this to parse this string
let s = "\n54766392632990,178.32.243.13,wfsdsfsdfs23432,\n54766393632990,178.32.243.13,"
s = s.split("\n");
let array = [];
for(let i=0;i<s.length;i++) {
let v = s[i].split(",178.32.243.13,");
for(let j=0;j<v.length;j++) {
if(!isNaN(parseInt(v[j]))) {
array.push(v[j]);
}
}
}
console.log(array);
