Extract sub string from a variable based on special characters in shell script

Question

I've a variable where I would like to extract the content surrounded by a special character. In my case the character is %.

The value stored in the variable goes this way:

"something.. : something.. %Required Value 1% something.. %Required Value 2% : something.. "

The response is filled with different special characters and the value is coming from a different script.

From the above response, I want to extract the values surrounded with %. The output I'm looking for is

Required Value 1
Required Value 2

oliv · Accepted Answer · 2018-09-20 08:49:58Z

3

Using awk:

awk -v RS='%' '(NR+1)%2' <<< "something.. : something.. %Required Value 1% something.. %Required Value 2% : something.. "
Required Value 1
Required Value 2

RS, the record separator, is set to %. The only statement prints all even record number, e.g. NR=2, 4, 6...

answered Sep 20, 2018 at 8:49

oliv

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stack0114106 · Accepted Answer · 2018-09-20 14:30:58Z

0

Using Perl

> export X="something.. : something.. %Required Value 1% something.. %Required Value 2% : something.. "
> perl -e ' BEGIN { $p=$ENV{X}; while($p=~m/(.+?)%(.+?)%(.+)/) { $p=$3; print "$2\n" }} '
Required Value 1
Required Value 2
>

answered Sep 20, 2018 at 14:30

stack0114106

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