Passing multiple arrays as parameters to a function

Question

I'm trying to pass a string array to a function, as well as a variable (which I've made into a single element array), but i'm not sure what the format is.

Function UpdateMembership ([string[]]$arr,[string[]]$group)
{
write-host $arr[0]
write-host $arr[1]
write-host $Group[0]
}

$OUs = @(
              "test1",
              "test2"
                )
$groupname  = @("group")

UpdateMembership ($Ous, $groupname)

$groupname = @()
$Ous = @()

I didnt understand it correctly. You mean to say that you wish to update the OU and groupname based on the input that you are taking in the function? Then use for loop and update it. Or directly call @OU and @Groupname in the updatemembership function — Ranadip Dutta
– Ranadip Dutta, Commented Apr 26, 2019 at 9:20

user6811411 · Accepted Answer · 2019-04-26 10:45:48Z

1

When invoking the function, parameters are NOT enclosed in parenthese nor delimited by a comma.

Like you do it, you force ONE array to be handed over to the function.

You may use parameter names

> UpdateMembership -arr $Ous -group $groupname
test1
test2
group

or simply rely on positional order

> UpdateMembership $Ous $groupname
test1
test2
group

answered Apr 26, 2019 at 10:45

user6811411

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Bernard Moeskops · Accepted Answer · 2019-04-26 09:19:39Z

0

Function UpdateMembership ([string[]]$arr,[string[]]$group)
{
    write-host $arr[0]
    write-host $arr[1]
    write-host $Group[0]
}

$OUs = @(
    "test1",
    "test2"
)
$groupname  = @("group")

UpdateMembership @Ous @groupname

$groupname = @()
$Ous = @()

answered Apr 26, 2019 at 9:19

Bernard Moeskops

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