PHP Parse error: syntax error, unexpected T_VARIABLE, expecting T_CATCH [closed]

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I'm trying a loop through a Facebook Graph API loop via a foreach loop but I'm getting this error: "PHP Parse error: syntax error, unexpected T_VARIABLE, expecting T_CATCH".

Any thoughts?

Here's the code:

// WRITING FIRST 50 FRIENDS LIKES

$i = 0;
foreach($userfriends[data] as $value) {

if($key == "id"){
    $friend_id = $value;        
}

try {
    $username = $friend_id;
    $uservar = '/'.$username.'/likes?fields=id,category&limit=20';
    $userlikes = $facebook->api($uservar);
}         

//  catch (FacebookApiException $e) {
//  error_log($e);
//  }

$id = $userlikes[$i][id];
$cat = $userlikes[$i][category];

// WRITING FRIEND LIKES TO DATABASE

$sql="INSERT INTO likes (like_id, category, friend_id) VALUES ('$id', '$cat', '$friend_id');";
mysql_query($sql,$con);
mysql_free_result($sql);
$i++;
}

mcgrailm · Accepted Answer · 2011-05-05 23:36:24Z

1

you have your catch commented out and it is expecting catch

answered May 5, 2011 at 23:36

mcgrailm

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McKracken · Accepted Answer · 2011-05-05 23:37:00Z

1

You have a try block without catch.

try {
$username = $friend_id;
$uservar = '/'.$username.'/likes?fields=id,category&limit=20';
$userlikes = $facebook->api($uservar);
} catch {

//exception happened
}

answered May 5, 2011 at 23:37

McKracken

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Sabeen Malik · Accepted Answer · 2011-05-05 23:36:22Z

0

you seem to have commented out the "catch" , re-enable it and the parse error would go away.

answered May 5, 2011 at 23:36

Sabeen Malik

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Rob Agar · Accepted Answer · 2011-05-05 23:37:39Z

0

Your catch block is commented out - either uncomment it or comment out the try as well. Every try must have at least one catch to handle any exceptions thrown inside the try.

answered May 5, 2011 at 23:37

Rob Agar

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