If I have the following array
let initialdates = [2019-12-07,2019-12-08, NaN-NaN-NaN]
Why does the following not work for my process in removing the NaN....
let initialdates = [2019 - 12 - 07, 2019 - 12 - 08, NaN - NaN - NaN]
for (let [index, dateField] of initialdates.entries()) {
if (isNaN(dateField)) {
initialdates[dateField] = "found issue";
}
}
console.log('the final array is: ' + initialdates);It still prints out...
the final array is: 2019-12-07,2019-12-02,NaN-NaN-NaN
initialdates[dateField] = "found issue";
should be
initialdates[index] = "found issue";
To answer your question. You have made a mistake in your code. Instead of modifying value in an index, you're giving the value itself.
initialdates[index] = "found issue";
And to replace the function with ES6, you can use filter on it.
const initialdates = [2019 - 12 - 07,2019-12-8, NaN-NaN-NaN];
const result = initialdates.filter(value => !isNaN(value));
console.log('the final array is: ' + result);
which doesn't contain NaN.
.filter(value=>value) and JS will handle that.
NaN values.You need to use the index instead of the value to overwrite the member.
let initialdates = [2019 - 12 - 07, 2019 - 12 - 08, NaN - NaN - NaN]
for (let [index, dateField] of initialdates.entries()) {
if (isNaN(dateField)) {
initialdates[index] = "found issue"; // <-- use 'index'
}
}
console.log('the final array is: ' + initialdates);The way you had it, you were adding a property named "NaN" to the array.
let initialdates = [2019 - 12 - 07, 2019 - 12 - 08, NaN - NaN - NaN]
initialdates = initialdates.filter(i=>i);
console.log('the final array is: ' + initialdates);If there is minus, yes a simple filter will remove NaN. But if they are dashes to separate date parts, you need to make them string.
2019 - 12 - 07is2000which is not a date.