I have two arrays-
$ar = array("a","b","c");
$xy = array("a","b","c","d","e");
I have to find out each element in $ar in $xy. If all elements are in $xy then it should return true.
I used in_array() but it returns true though one element is found.
Any help is appreciated. Thanks.
array_diff[Docs] returns an array containing all the entries from the first array that are not present in any of the other arrays:
$return = (bool) count(array_diff($ar, $xy));
$ar which are not in $xy
count(...) > 0 already gives you your boolean value. No need for the manual assignment: $return = (count(array_diff($ar, $xy)) > 0);
You might use array_intersect
With some additional code (thanks Brendan):
return (count($ar) == count(array_intersect($xy, $ar)));
return (count($ar) == count(array_intersect($xy,$ar)));?$found = true;
foreach ($ar as $r) {
if (!in_array($r, $xy)) {
$found = false;
break;
}
}
function in_array_all($x, $y){
$true = 0;
$count = count($x);
foreach($x as $key => $value){
if(in_array($value, $y)) $true++;
}
return ($true == $count)? true: false;
}
$ar = array("a","b","c"); $xy = array("a","b","c","d","e");
echo in_array_all($ar, $xy);
function array_equal($ar, $xy) {
return !array_diff($ar, $xy) && !array_diff($ar, $xy);
}
This is how you use it.
if(array_equal($ar, $xy) {
// etc...
}