Replace a Substring of a String in Velocity Template Language

Question

I want to replace a part of a string in Velocity Template Language with another string.

For Example:

#set($a = "Hello")
#set($b = "+")

I want to replace ll in Hello with ++. The output should be He++o

Please help me

Thanks Kishore

Mark McLaren · Accepted Answer · 2011-12-15 10:10:06Z

80

By default you can use the methods of the Java String object:

#set( $a = "Hello" )
#set( $b = $a.replace("l", "+") )
${b}

will produce He++o and you can also use velocity variables as arguments to your method calls, e.g.:

#set( $a = "Hello" )
#set( $b = "+" )
#set( $c = $a.replace("l", ${b}) )
${c}

answered Dec 15, 2011 at 10:10

Mark McLaren

11.5k3 gold badges52 silver badges81 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

Koray Tugay Over a year ago

I just want to add a little note for future visitors: I had a very simple conversion in my velocity template from ö to oe, but it seemed like it was not working. Anyway, after a while I realised the character set of input was cp-1252 and jvm was working with utf-8 so the "ü" in the template was not the "ü" I was after..

fIwJlxSzApHEZIl Over a year ago

what is the purpose of the curly braces here?

Evadman Over a year ago

@anon58192932 Curly braces are for formal notion. In this specific example,they are not absolutely required. $b is an identical reference as ${b}. Link: Apache

Collectives™ on Stack Overflow

Replace a Substring of a String in Velocity Template Language

1 Answer 1

3 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

3 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related