How do I get an integer to fill 0's to a fixed width in python 3.2 using the format attribute? Example:
a = 1
print('{0:3}'.format(a))
gives ' 1' instead of '001' I want. In python 2.x, I know that this can be done using
print "%03d" % number.
I checked the python 3 string documentation but wasn't able to get this.
http://docs.python.org/release/3.2/library/string.html#format-specification-mini-language
Thanks.
Prefix the width with a 0:
>>> '{0:03}'.format(1)
'001'
Also, you don't need the place-marker in recent versions of Python (not sure which, but at least 2.7 and 3.1):
>>> '{:03}'.format(1)
'001'
Better:
number=12
print(f'number is equal to {number:03d}')
There is built-in string method .zfill for filling 0-s:
>>> str(42).zfill(5)
'00042'
>>> str(42).zfill(2)
'42'
bin(42)[2:].zfill(7) gives '0101010'. I don't know how'd I'd make the other answers work.In python 3, the prefered way is as follows:
For example:
a = 20
print(f"number is {a :03}")
Note that there is no space after the colon, otherwise the leading zero has no effect.
