Bash - Parse associative Array to JSON with k-v [duplicate]

Question

The example here:

#!/bin/bash

declare -A rep_hostname
rep_hostname=( [test1]='172.1.1.1' [test2]='172.1.1.2' [test3]='172.1.1.3' )

json=$(
        jo members="$(
                jo -a "${rep_hostname[@]}" |
                jq -c 'to_entries | map({ "_id": .key, "host": .value })'
        )"
)

echo "$json"

outputs the following:

{
    "members":[
      {"_id":0,"host":"172.1.1.3:2701"},
      {"_id":1,"host":"172.1.1.2:2701"},
      {"_id":2,"host":"172.1.1.1:2701"}
    ]
}

How to make the following JSON?

{
    "test1":"172.1.1",
    "test2":"172.1.1.2",
    "test3":"172.1.1.3"
}

What does the associative array have to do with this? If all you have is the JSON, you can use jq to parse it and produce the desired JSON. If you are starting with the associative array, you don't need to define json in the first place; you can work directly with the array. — chepner
– chepner, Commented Sep 8, 2021 at 13:08
So again, what does the value you assign to json have to do with this? — chepner
– chepner, Commented Sep 8, 2021 at 13:38

Dfaure · Accepted Answer · 2021-09-08 13:11:27Z

1

Cf. https://unix.stackexchange.com/questions/366581/bash-associative-array-printing

jo $(paste -d= <(printf "%s\n" "${!rep_hostname[@]}") <(printf "%s\n" "${rep_hostname[@]}"))

The printf commands will output associative keys and values by lines, the paste -d= ... will merge the produced lines bound by an = sign and lastly the jo processor will build a JSON from that.

A more iterative equivalent could also be:

for i in "${!rep_hostname[@]}";do printf "%s=%s\n" "$i" "${rep_hostname[$i]}";done | jo

edited Sep 8, 2021 at 13:11

answered Sep 8, 2021 at 12:59

Dfaure

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