Best way to sort array based of different sets of data? [duplicate]

Question

var array = [{value:"13",type:"Fruit"},{value:"61",type:"Animal"},
             {value:"19",type:"Fruit"},{value:"71",type:"Animal"},
             {value:"12",type:"Fruit"},{value:"15",type:"Fruit"}, 
             {value:"11",type:"Plant"},{value:"10",type:"Fruit"}, 
             {value:"16",type:"Plant"}]

What is the best/optimized way to sort this array such that I get all elements of type Fruit first and then the elements of type Animal (by picking elements from end of array).

expectedOutput = [{value:"10",type:"Fruit"}, 
             {value:"15",type:"Fruit"},{value:"12",type:"Fruits"},
             {value:"19",type:"Fruit"},{value:"13",type:"Fruit"},
             {value:"71",type:"Animal"},{value:"61",type:"Animal"}, 
             {value:"16",type:"Plant"},{value:"11",type:"Plant"}]

Note:- I don't need to sort it Alphabetically. It must be sort depending upon the specific type.

Spectric · Accepted Answer · 2021-11-09 20:50:40Z

1

You can store the order of the type properties in an array, then subtract the index of the type property when sorting to determine precedence:

const order = ["Fruits", "Animal"]

var array = [{value:"13",type:"Fruit"},{value:"61",type:"Animal"},
             {value:"19",type:"Fruit"},{value:"71",type:"Animal"},
             {value:"12",type:"Fruit"},{value:"15",type:"Fruit"}] 

const sorted = array.sort((a,b) => order.indexOf(a.type) - order.indexOf(b.type))

console.log(sorted)

answered Nov 9, 2021 at 20:50

Spectric

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