BASH script to pass variables without substitution into new script

Question

As part of a system build script I have a script that creates various files and configurations.

However one part of the build script creates a new script that contains variables that I don't want resolved when the build script runs. Code snippet example

cat - > /etc/profile.d/mymotd.sh <<EOF
hostname=`uname -n`
echo -e "Hostname is $hostname"
EOF

I have tried all sorts of combinations of ' and " and ( and [ but I cannot get the script to send the content without substituting the values and placing the substitutes in the new script rather than the original text.

Ideas?

Jonathan Callen · Accepted Answer · 2011-09-26 03:14:40Z

26

The easiest method, assuming you don't want anything to be substituted in the here doc, is to put the EOF marker in quotes, like this:

cat - > /etc/profile.d/mymotd.sh <<'EOF'
hostname=`uname -n`
echo -e "Hostname is $hostname"
EOF

answered Sep 26, 2011 at 3:14

Jonathan Callen

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ott-- · Accepted Answer · 2011-09-25 23:55:51Z

12

Easiest is to escape the $

echo -e "Hostname is \$hostname"

answered Sep 25, 2011 at 23:55

ott--

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