#!/bin/bash
declare -a matrix
num_rows=4
num_columns=5
for ((i=1;i<=num_rows;i++)) do
for ((j=1;j<=num_columns;j++)) do
matrix[$i,$j]=$j
done
done
f1="%$((${#num_rows}+1))s"
f2=" %9s"
printf "$f1" ''
for ((i=1;i<=num_rows;i++)) do
printf "$f2" $i
done
echo
for ((j=1;j<=num_columns;j++)) do
printf "$f1" $j
for ((i=1;i<=num_rows;i++)) do
printf "$f2" ${matrix[$i,$j]}
done
echo
done
=> run result:
1 2 3 4
1 1 1 1 1
2 2 2 2 2
3 3 3 3 3
4 4 4 4 4
5 5 5 5 5
======================== #!/bin/bash declare -a matrix num_rows=4 num_columns=5
for ((i=1;i<=num_rows;i++)) do
for ((j=1;j<=num_columns;j++)) do
matrix[$i,$j]=$i
done
done
f1="%$((${#num_rows}+1))s"
f2=" %9s"
printf "$f1" ''
for ((i=1;i<=num_rows;i++)) do
printf "$f2" $i
done
echo
for ((j=1;j<=num_columns;j++)) do
printf "$f1" $j
for ((i=1;i<=num_rows;i++)) do
printf "$f2" ${matrix[$i,$j]}
done
echo
done
if change assignment to the array from $j to $i the result:
1 2 3 4
1 4 4 4 4
2 4 4 4 4
3 4 4 4 4
4 4 4 4 4
5 4 4 4 4
This seems because bash doesn't support multi-dimensional array?
Is there a way to use two dimensional array with bash?
${arr[x,y]}is exactly the same as${arr[y]}, as the comma is a math operator that simply evaluates to the value on its right.