HTML- and PHP-code inside an PHP 'if statement'

Question

What if I want to have HTML code inside my 'if' statement, and then php code in the 'else' part? What do I do? I have tried this, but with no luck..

<?php

session_start();

if ($_SESSION['bnavn']) : ?>

   'HTML-code'

<?php else : ?>

    'PHP-code'
    
<?php endif: ?>

I have also tried this, but also with no luck:

<?php

    session_start();

    if ($_SESSION['bnavn']) : ?>

       'HTML-code'

    <?php else : ?>

        <?php 'PHP-code' ?>
        
    <?php endif: ?>

@LukePark yes it does php.net/manual/en/control-structures.alternative-syntax.php — rjdown
– rjdown, Commented Feb 27, 2016 at 23:00
@Troels read that link above, take note of the semi-colon after the endif — rjdown
– rjdown, Commented Feb 27, 2016 at 23:02
The second way should work (besides the colon at the end that should be a semi-colon). What is the problem? Why not provide the exact code you are trying with? — trincot
– trincot, Commented Feb 27, 2016 at 23:08
An entire page is inside the if statement. This page should only be shown if the statement is true, and if not, it should with PHP-code in the 'else' part 'die' like: <?php die ("You are not logged in!"); ?> — Troels
– Troels, Commented Feb 27, 2016 at 23:59

Community · Accepted Answer · 2017-05-23 12:07:31Z

0

I have figured it out! I found this link: PHP Session Destroy on Log Out Button

I made the if statement as one of the answers said, and changed my page.html to page.php. I do not know if it have to .php instead of .html, but not it works!

edited May 23, 2017 at 12:07

CommunityBot

11 silver badge

answered Feb 28, 2016 at 0:25

Troels

111 bronze badge

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