Inserting Variable into sh Script Command [duplicate]

Question

#!/bin/sh -f

set proj_dir="OutputDir"
for projname in lib proj1 proj2
do
    mv ./scripts/$projname_BYTECODE ./$proj_dir/scripts/$projname
done

A very simple example of what is not working well for me. $projname_BYTECODE is being interpreted as a variable name but _BYTECODE is actually part of the folder name. Suggestions?

You know, I "tried" that, but the syntax highlighting on gedit said it was still one variable so I did not actually try it. That does seem to have worked, though. You should answer the question. — fm_user8
– fm_user8, Commented Apr 14, 2017 at 17:41
As an aside; you've got some quoting bugs still present -- shellcheck.net will catch them. — Charles Duffy
– Charles Duffy, Commented Apr 14, 2017 at 17:53
Yeah, I realized I put that in there accidentally when making this post. My script did not have that but copying&pasting was not working from my Linux VM at the time. So when I was typing it up, I mixed in some Tcl/Tk that I am unfortunately learning recently. — fm_user8
– fm_user8, Commented Apr 15, 2017 at 18:02

Community · Accepted Answer · 2017-05-23 11:46:58Z

4

Use ${X} instead of $X, so in your example ${projname}_BYTECODE should do the trick. Have a look at this question for more information: When do we need curly braces in variables using Bash?

edited May 23, 2017 at 11:46

CommunityBot

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answered Apr 14, 2017 at 17:43

C-Otto

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