PHP - Convert array in class variables

Question

How can I convert array (assoc or seq) into class variables:

I have this array

[
    "uuidtype"=>4,
    "data"=>[
        "name"=>"Arthur",
        "age"=>"unknown"
    ]
]

I have this class:

class Example{
    public static function ___g($var_name, $val){
        // static $$varname = $val; Doesn't work
        // self::${(string)$varname} = $val; Doesn't work
    }
}

I want this:

class Example{
    public static $uuidtype = 4;
    public static $data;

    ...
}

my vote would be to define a basic class and use magic __get/__call methods, at which point this array would become a property of this class instance, and your __get/__call methods would interact with the array data and act accordingly — Scuzzy
– Scuzzy, Commented Apr 9, 2018 at 23:02
Also, tell us about the problem you're trying to solve and tell us why you think this is the solution to your problem? — Scuzzy
– Scuzzy, Commented Apr 9, 2018 at 23:04
Class properties are for defining static values, not runtime data. Runtime data would be in the object itself, so either in a method, or specifically get/set methods, or the constructor - whichever makes sense for what you're doing. — James
– James, Commented Apr 9, 2018 at 23:05

Máxima Alekz · Accepted Answer · 2018-04-10 18:16:44Z

0

You could create an Array and then cast it as object, so:

$arr = [
    "uuidtype"=>4,
    "data"=>[
        "name"=>"Arthur",
        "age"=>"unknown"
    ]
]

$as_class = (object) $arr;

echo $as_class->uuidtype; //Works ;)

I am not sure about performance, but works for me.

answered Apr 10, 2018 at 18:16

Máxima Alekz

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Nadir Latif · Accepted Answer · 2018-04-11 04:37:47Z

0

You can also use the Php __get magic method. It allows dynamically creating object properties. See http://php.net/manual/en/language.oop5.overloading.php#object.get. A similar question was asked on: How do I dynamically write a PHP object property name?

answered Apr 11, 2018 at 4:37

Nadir Latif

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