Remove object from array of objects based on object key value

Question

I have an object like

let arr = [
    {isManaged: true, id:1},
    {isManaged: false, id:2},
    {isManaged:false, id:3}
]

to get the values which are true, i do

arr.map(shift => ({
    id: shift.id,
    isPartnerManaged: shift.isManaged,
}))

but this will only return me the values where i true, now, I want to remove them from the array of objects. I tried to use the array.pop but i don't know what index to feed it. Any ideeas?

Possible duplicate of Filter an array based on an object property — str
– str, Commented Jun 13, 2019 at 12:08

horia · Accepted Answer · 2019-06-13 12:08:58Z

3

arr = arr.filter(shift => shift.isManaged);

answered Jun 13, 2019 at 12:08

horia

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Comments

Nina Scholz · Accepted Answer · 2019-06-13 12:10:32Z

-1

You could filter the array and build new objects.

var array = [{ isManaged: true, id: 1 }, { isManaged: false, id: 2 }, { isManaged: false, id: 3 }],
    result = array
        .filter(({ isManaged }) => isManaged)
        .map(({ isManaged: isPartnerManaged, id }) => ({ id, isPartnerManaged }));

console.log(result);

answered Jun 13, 2019 at 12:10

Nina Scholz

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