Python - Find index of given element in list using recursion [duplicate]

Question

def ind(e, L):
    if e not in L:
        return 0
    else:
        return 1 + ind(e, L[:1]) 
assert ind(42, [55, 77, 42, 12, 42, 100])

I want the index(so in this case I need 2), but the code always seems to give me the numbers instead. Also I can't use the index function in Python.

Please help if you got some time.

cmplx96 · Accepted Answer · 2020-09-22 12:12:43Z

1

def ind(e, L):
    if e == L[0]:
        return 0
    else:
        return 1 + ind(e, L[1:])

answered Sep 22, 2020 at 12:12

cmplx96

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