How can I add consecutive numbers to a string in a text file, with two strings each having the same number?
example:
id="picture-"
id="picture-"
id="picture-"
id="picture-"
...
result:
id="picture-1"
id="picture-1"
id="picture-2"
id="picture-2"
...
The number is not at the last position in the lines. I have tried this:
perl -pe 's/picture\-/$& . ++$n/ge' index.txt
But this adds the numbers so, that every string gets another number.
Any help would be appreciated.
You can always do:
perl -pe 's/picture-\K/1+($n++>>1)/ge' index.txt
To generate the data from scratch:
seq -f 'id="picture-%.0f"' 10 | sed p
A slight alteration to your perl one-liner:
perl -mPOSIX -pe 's/picture\-/$& . POSIX::ceil(++$n\/2)/ge' index.txt
The number appended is now half-n, rounded up, so the result only increases every other line.
$ awk -F '"' 'BEGIN { OFS=FS; n=1 } { $2 = sprintf("%s%d", $2, ++n/2); print }' file
id="picture-1"
id="picture-1"
id="picture-2"
id="picture-2"
Here, we treat each line as a set of "-delimited fields. The second field is modified by awk by adding an integer to the end of it. The integer is incremented by one for each line, but also divided by two. The effect is that the number in the output would be incremented by one every second line (due to rounding when the number is used with the %d format in sprintf()).
I would use a for loop.
Assumptions:
#!/bin/sh
# Define constants
prefix="picture-"
max_count=30
# For/Next style loop
for i in ((i=1;i<=$max_count;i++))
do
echo "${prefix}${i}"
end
zoid=foooracid=base? What if you have "picture" text that's elsewhere? Would it - should it - throw off the numbering?