PHP value in an array

Question

Hi I'm working on a checking a given array for a certain value.

my array looks like

while($row = mysqli_fetch_array($result)){

    $positions[] = array( 'pos' => $row['pos'], 'mark' => $row['mark'] );
}

I'm trying to get the info from it with a method like

<?php
    if(in_array('1', $positions)){
          echo "x";
    }
?>

This I know the value '1' is in the array but the x isn't being sent as out put. any suggestions on how to get "1" to be recognized as being in the array?

Edit: I realize that this is an array inside of an array. is it possible to combine in_array() to say something like: "is the value '1' inside one of these arrays"

Corbin · Accepted Answer · 2012-04-27 01:40:18Z

3

in_array is not recursive. You're checking if 1 is in an array of arrays which doesn't make sense. You'll have to loop over each element and check that way.

$in = false;
foreach ($positions as $pos) {
    if (in_array(1, $pos)) {
        $in = true;
        break;
    }
}

answered Apr 27, 2012 at 1:40

Corbin

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Comments

Niet the Dark Absol · Accepted Answer · 2012-04-27 01:40:23Z

1

in_array only checks the first level. In this case, it only sees a bunch of arrays, no numbers of any kind. Instead, consider looping through the array with foreach, and check if that 1 is where you expect it to be.

answered Apr 27, 2012 at 1:40

Niet the Dark Absol

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Comments

Kep · Accepted Answer · 2012-04-27 01:41:24Z

1

That's because $positions is an array of arrays (a multi-dimensional array). It contains no simple '1'.

Try a foreach-loop instead:

foreach($postions as $value)
    if ($value["pos"] == '1')
        echo "x ".$value["mark"];

answered Apr 27, 2012 at 1:41

Kep

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Comments

Blair McMillan · Accepted Answer · 2012-04-27 01:41:18Z

0

The problem is that 1 isn't actually in the array. It's in one of the array's within the array. You are comparing the value 1 to the value Array which obviously isn't the same.

Something like this should get you started:

foreach ($positions as $position) {
    if ($position['pos'] == 1) {
        echo "x";
        break;
    }
}

answered Apr 27, 2012 at 1:41

Blair McMillan

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Comments

Jonathan · Accepted Answer · 2012-04-27 01:41:54Z

0

Your array $positions is recursive, due to the fact that you use $positions[] in your first snippet. in_array is not recursive (see the PHP manual). Therefore, you need a custom function which works with recursive arrays (source):

<?php
function in_arrayr( $needle, $haystack ) {
    foreach( $haystack as $v ){
        if( $needle == $v )
            return true;
        elseif( is_array( $v ) )
            if( in_arrayr( $needle, $v ) )
                return true;
    }
    return false;
}
?>

Instead of calling in_array() in your script, you should now call in_arrayr().

answered Apr 27, 2012 at 1:41

Jonathan

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