Regular Expression Match/Replace

Question

What would be the equivalent of this (Javascript) in python?

var patt = /sub(\d+)\.domain\.com\/(\d+)/
  , m    = url.match(patt)
  , url = 'http://sub' + m[1] + '.domain.com/' + m[2]

I'm new at Python and not quite understanding the regex system yet :(

@MikePennington ah, yes...sorry forgot to add that!

Pastor Bones
– Pastor Bones

2012-05-07 22:16:58 +00:00
Commented May 7, 2012 at 22:16 — Pastor Bones
– Pastor Bones, Commented May 7, 2012 at 22:16

dfb · Accepted Answer · 2012-05-07 22:16:39Z

1

You've pretty much already got it

>>> x = re.search("sub(\d+)\.domain\.com\/(\d+)","sub123.domain.com/546").groups()
('123', '546')
>>> url = "%s blah blah %s" % x

answered May 7, 2012 at 22:16

dfb

13.3k2 gold badges33 silver badges53 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Ansari · Accepted Answer · 2012-05-07 22:25:49Z

1

The rough equivalent of your code in Python would be

import re

url = 'http://sub36.domain.com/54'

patt = re.compile("sub(\d+)\.domain\.com\/(\d+)")
m = patt.search(url)
url = 'http://sub'+m.group(1)+'.domain.com/'+m.group(2)

edited May 7, 2012 at 22:25

answered May 7, 2012 at 22:19

Ansari

8,2182 gold badges25 silver badges35 bronze badges

Collectives™ on Stack Overflow

Regular Expression Match/Replace

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related