Textview causing java.lang.ClassCastException: android.widget.TextView

Question

I have three textviews and applied clickevent on them, but when i click on any of them the they cause Forceclose error in application. i have also tried changing ids textviews and then clean project and ran the project still that error is not removed.

My XML code is

for one textview

<LinearLayout
        android:id="@+id/LL_fb" 
        android:layout_width="180px"
        android:layout_height="27px"
        android:layout_above="@+id/txt_msg_regs"
        android:layout_alignLeft="@+id/LL_signup"
        android:layout_marginBottom="25dp"
        android:background="@drawable/facebook" >        
    <TextView
        android:id="@+id/btn_txt_fb"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="Connect with facebook"
        android:layout_gravity="center_vertical"
        android:layout_marginLeft="23dp"
        android:layout_marginTop="1dp"
        android:clickable="true"
        android:textColor="#FFFFFF" />
    </LinearLayout>

for second textview

<LinearLayout 
        android:id="@+id/LL_signup"
        android:layout_width="180px"
        android:layout_height="29px"
        android:layout_above="@+id/textView1"
        android:layout_alignLeft="@+id/LL_login"
        android:background="@drawable/lmyic_signup">

    <TextView
        android:id="@+id/btn_txt_sinup"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="signup with email"
        android:layout_gravity="center_vertical"
        android:layout_marginLeft="25dp"
        android:layout_marginTop="1dp"
        android:clickable="true"
        android:textColor="#FFFFFF" />

    </LinearLayout>

for third one

 <LinearLayout 
            android:id="@+id/LL_login"
            android:layout_width="180px"
                android:layout_height="29px"
                android:layout_alignParentBottom="true"
                android:layout_centerHorizontal="true"
                android:layout_marginBottom="69dp"
                android:background="@drawable/lmyic_login">
        <TextView
            android:id="@+id/btn_txt_login"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:text="Log in"
            android:layout_gravity="center_vertical"
            android:layout_marginLeft="70dp"
            android:layout_marginTop="1dp"
            android:textColor="#FFFFFF" 
            android:clickable="true"/> 
        </LinearLayout>

this is my android code. This class name in intent are also correct and i verified them.

TextView img_login;
img_login = (TextView)findViewById(R.id.btn_txt_login);
 img_login.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub

                if(v.getId() == img_login.getId())
                {
                Intent i_lin = new Intent(LockmeifyoucanActivity.this,lmiyc_login.class);
                startActivity(i_lin);
                }                   
            }
        });

Please Tell me what is wrong with this. If logcat is needed then ask me for it....

where is btn_txt_login ? Please post the XMl having btn_txt_login. — Dheeresh Singh
– Dheeresh Singh, Commented May 11, 2012 at 12:21
@SamirMangroliya hello, i edited my question it is btn_txt_login in my xml code by mistake it was written like that.... — JAaVA
– JAaVA, Commented May 11, 2012 at 12:32
post your logcat i'm sure you have some issue in lmiyc_login.class activity — ρяσѕρєя K
– ρяσѕρєя K, Commented May 11, 2012 at 12:38
you have try if(v.getId()==(R.id.btn_txt_login)) instead of v.getId() == img_login.getId() — ρяσѕρєя K
– ρяσѕρєя K, Commented May 11, 2012 at 12:40

Dheeresh Singh · Accepted Answer · 2012-05-11 12:24:17Z

1

Please post the complete XMl so that we can view the btn_txt_login in that.

It looks it is button because "findViewById(R.id.btn_txt_login);" would return null if this "btn_txt_login" id is not in xml.

answered May 11, 2012 at 12:24

Dheeresh Singh

15.7k3 gold badges40 silver badges36 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Dheeresh Singh Over a year ago

btn_txt_login should be button on UI and txt_login is textview as we can see. I think due to same almost same name you would have done this.

Dheeresh Singh Over a year ago

iff query has been resolved please vote/accept any answer found close to your answer to finish this story and make stack Clear for all....

ρяσѕρєя K · Accepted Answer · 2012-05-11 12:50:29Z

1

you have some problem with textview in lmiyc_login activity.in lmiyc_login corrent line number 46 which maybe:

TextView txtview;
txtview = (TextView)yourlayout.findViewById(R.id.txtviewid);

answered May 11, 2012 at 12:50

ρяσѕρєя K

133k54 gold badges203 silver badges216 bronze badges

3 Comments

JAaVA Over a year ago

this lines of code are of my another page when i click on login btn on home page then this screen(lmiyc_login) should be open and it also has one login btn same as it is in home screen.

ρяσѕρєя K Over a year ago

if you give a pastbin link for lmyic_login_page xml then your problem will solve in sort time

JAaVA Over a year ago

@all The problem is solved. The problem was in another page. redeclared all imageview as textview in lmiyc_login page.

Rawkode · Accepted Answer · 2012-05-11 12:20:24Z

0

findViewById(R.id.btn_txt_login);

Is this really a TextView or do you have a Button in your layout as well? I think you're trying to cast a Button to a TextView

answered May 11, 2012 at 12:20

Rawkode

22.7k5 gold badges42 silver badges46 bronze badges

Comments

avimak · Accepted Answer · 2012-05-11 12:20:52Z

0

Wrong resource ID...

img_login = (TextView)findViewById(R.id.btn_txt_login);

according to your XML should be

img_login = (TextView)findViewById(R.id.txt_login);

etc..

answered May 11, 2012 at 12:20

avimak

1,62811 silver badges18 bronze badges

Comments

Nikhil Lamba · Accepted Answer · 2012-05-11 12:34:17Z

0

change ur code with this

TextView img_login;
 img_login = (TextView)findViewById(R.id.txt_login);
   img_login.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub

            if(v.getId().equals(img_login.getId()))
            {
            Intent i_lin = new Intent(LockmeifyoucanActivity.this,lmiyc_login.class);
            startActivity(i_lin);
            }                   
        }
    });

answered May 11, 2012 at 12:34

Nikhil Lamba

6031 gold badge6 silver badges17 bronze badges

1 Comment

Nikhil Lamba Over a year ago

hahahaha u wrote btn_txt_login n i wrote this R.id.txt_login and u wrote this v.getId() == img_login.getId() nd i wrote this v.getId().equals(img_login.getId()) nd u say its already therr great :)

Rodrigo · Accepted Answer · 2012-05-11 12:46:47Z

0

To resolve this error quickly, set one break point at line:

View view = findViewById(R.id.btn_txt_login);

Then, see on locals tab which component is, looking at gen/R.java.

answered May 11, 2012 at 12:46

Rodrigo

4,8125 gold badges44 silver badges78 bronze badges

Comments

Dheeresh Singh · Accepted Answer · 2012-05-11 12:59:19Z

0

these are lines from 42-48

 setContentView(R.layout.lmyic_login_page);                 
  txtBack = (TextView)findViewById(R.id.ImgViewTxtBack);          txtBack.setTypeface(null,Typeface.BOLD);
   iv_login = (ImageView)findViewById(R.id.Txtlogin);
   iv_login.setOnClickListener(this);
   iv_sign_up = (ImageView)findViewById(R.id.TxtSignup);

I think problem is with iv_login = (ImageView)findViewById(R.id.Txtlogin); – Dheeresh Singh 1 min ago edit because this is 46 line and it should be textview and you are castin it in Imageview – Dheeresh Singh just now edit

answered May 11, 2012 at 12:59

Dheeresh Singh

15.7k3 gold badges40 silver badges36 bronze badges

Comments

Maruf · Accepted Answer · 2015-03-26 17:07:35Z

0

if you have duplicate resource Id, that will throw ClasscastException. So make sure you don't have duplicate element id throughout the whole project.

answered Mar 26, 2015 at 17:07

Maruf

1

Collectives™ on Stack Overflow

Textview causing java.lang.ClassCastException: android.widget.TextView

8 Answers 8

2 Comments

3 Comments

Comments

Comments

1 Comment

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

8 Answers 8

2 Comments

3 Comments

Comments

Comments

1 Comment

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related