Sorting a 2D array by a column [duplicate]

Question

Trying to sort an array by name so I can display an alphabetical list.

Here's a snippet of code:

sort($stores);

for ($i = 0; $i < count($stores); $i++) {
    echo $stores[$i]['name'];
}

I have a basic understanding of what needs to be done, I'm just not sure how to pass the 'name' part of the array to the sort() function. Perhaps I need to use a different function?

This question is missing its minimal reproducible example.

mickmackusa
– mickmackusa ♦

2025-01-25 20:02:55 +00:00
Commented Jan 25 at 20:02 — mickmackusa
– mickmackusa ♦, Commented Jan 25 at 20:02

deceze · Accepted Answer · 2012-07-12 07:44:41Z

2

Use a custom sort function:

usort($stores, function ($a, $b) {
    return strcmp($a['name'], $b['name']);
});

answered Jul 12, 2012 at 7:44

deceze♦

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Comments

Ozair Kafray · Accepted Answer · 2012-07-12 07:52:43Z

2

You can use usort to sort an array by values using a customized comparison function.

By custom here we mean an array of custom object types.

function compare($a, $b)
{
    return strcmp($a['name'], $b['name']);
}

usort($stores, "compare");

edited Jul 12, 2012 at 7:52

answered Jul 12, 2012 at 7:44

Ozair Kafray

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