How to judge a variable's type as string or integer

Question

This is my code:

if [ $value == "^[[:digit:]]*$" ]
then
    echo "number"
else
    echo "other"
fi

It seems that the program never echoes "number" even if I set value=1.

Ignacio Vazquez-Abrams · Accepted Answer · 2012-07-17 05:44:44Z

7

test doesn't do regexs.

[[ $value =~ ^[0-9]+$ ]]

answered Jul 17, 2012 at 5:44

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3 Comments

+1 Beat me to it. Also important is that the OP needs to not have quotes around the regex. Plus the question was missing a then ...

could I ask that what ~ refers to?

Short answer: =~ is a distinct operator, just like == and !=