JavaScript and PHP in code - whats the difference?

Question

I have this code in my JavaScript part:

var opConfig = new Product.Options(<?php echo $this->getJsonConfig(); ?>);

The PHP call returns me some string, to make it easy, lets say the string is abcd. So this code results in:

var opConfig = new Product.Options(abcd);

Now, some lines later, I have this code:

this.opConfig = new Product.Options(opconfig);

The opconfig variable has the same string abcd, but the results are different, this.opConfig does not look like it looked before. So is there a difference in how I use the string as param? Something I am missing? For me, it should always be the same call, namely:

new Product.Options(abcd)

Ideas?

Addition: The full call in the JS code looks like that:

var opConfig = new Product.Options({"16":{"26":{"price":5,"oldPrice":5,"priceValue":"5.0000","type":"fixed","excludeTax":5,"includeTax":5},"28":{"price":8,"oldPrice":8,"priceValue":"8.0000","type":"fixed","excludeTax":8,"includeTax":8},"27":{"price":10,"oldPrice":10,"priceValue":"10.0000","type":"fixed","excludeTax":10,"includeTax":10}},"14":{"price":0,"oldPrice":0,"priceValue":"0.0000","type":"fixed","excludeTax":0,"includeTax":0},"15":{"price":0,"oldPrice":0,"priceValue":"0.0000","type":"fixed","excludeTax":0,"includeTax":0}});

The param reaches the called function as object, no idea why. Calling it the other way, the same string seems to reach it as string. Can anybody help?

Should not string be used in ' or "?

Leri
– Leri

2012-07-25 14:32:05 +00:00
Commented Jul 25, 2012 at 14:32 — Leri
– Leri, Commented Jul 25, 2012 at 14:32
abcd is not a string. "abcd" would be.

JJJ
– JJJ

2012-07-25 14:32:19 +00:00
Commented Jul 25, 2012 at 14:32 — JJJ
– JJJ, Commented Jul 25, 2012 at 14:32

Curtis · Accepted Answer · 2012-07-25 14:31:36Z

2

Change to:

var opConfig = new Product.Options('<?php echo $this->getJsonConfig(); ?>');

opconfig is a string variable, so its fine passing that as a parameter.

Whereas your PHP code will render:

var opConfig = new Product.Options(abcd);

abcd is not a string variable. Therefore you need to put this in speech marks so that it becomes a string object. Your output would now be:

var opConfig = new Product.Options('abcd');

answered Jul 25, 2012 at 14:31

Curtis

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Comments

nnnnnn · Accepted Answer · 2012-07-25 14:32:26Z

0

If you have new Product.Options(abcd) then abcd is a variable name, not a string. You need to add quotes so that it ends up as new Product.Options('abcd'):

var opConfig = new Product.Options('<?php echo $this->getJsonConfig(); ?>');
// OR
var opConfig = new Product.Options("<?php echo $this->getJsonConfig(); ?>");

Either way you need to be sure your PHP output escapes any characters that might "break" the string literal, e.g., single-quotes (in the first one) or double-quotes (in the second one), or newlines (in either).

answered Jul 25, 2012 at 14:32

nnnnnn

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kante · Accepted Answer · 2012-07-25 14:32:46Z

0

I can see you're missing quotes:

var opConfig = new Product.Options('<?php echo $this->getJsonConfig(); ?>');

answered Jul 25, 2012 at 14:32

kante

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Comments

Koti · Accepted Answer · 2012-07-25 14:32:53Z

0

Change the below line

var opConfig = new Product.Options(<?php echo $this->getJsonConfig(); ?>);

to

var opConfig = new Product.Options('<?php echo $this->getJsonConfig(); ?>');

answered Jul 25, 2012 at 14:32

Koti

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