Sort NSMutableArray and sort another NSMutableArray along

Question

It's possible to sort an array like this:

MutableArray  = [NSMutableArray arrayWithObjects:@"5",@"1",@"7,@"9",@"4", nil];

to (start big ends small):

MutableArray  = [NSMutableArray arrayWithObjects:@"9",@"7",@"5,@"4",@"1", nil];

Is it also possible to sort two arrays:

MutableArray  = [NSMutableArray arrayWithObjects:@"5",@"1",@"7",@"9",@"4", nil];
MutableArray  = [NSMutableArray arrayWithObjects:@"Andy",@"Mike",@"Bob",@"Amy",@"Alex", nil];

to (from big to small, but Andy got 5 point, Mike got 1 and so on):

MutableArray  = [NSMutableArray arrayWithObjects:@"9",@"7",@"5",@"4",@"1", nil];
MutableArray  = [NSMutableArray arrayWithObjects:@"Amy",@"Bob",@"Andy",@"Alex",@"Mike", nil];

Is it possible to order them as a couple?
Thanks in Advance :)

Because an NSDictionary can hold keys (players) and values (scores). So when you sort one, you automatically sort both. — WhoaItsAFactorial
– WhoaItsAFactorial, Commented Aug 10, 2012 at 16:38
If you don't want a dictionary, objects would work too. (Anything's better than matching parallel arrays.) — Phillip Mills
– Phillip Mills, Commented Aug 10, 2012 at 16:45

Anne · Accepted Answer · 2012-08-10 20:37:40Z

2

Example how to sort arrayOne ascending and sort arrayTwo along:

NSMutableArray *arrayOne  = [NSMutableArray arrayWithObjects:@"5",@"1",@"7",@"9",@"4", nil];
NSMutableArray *arrayTwo = [NSMutableArray arrayWithObjects:@"Andy",@"Mike",@"Bob",@"Amy",@"Alex", nil];

NSDictionary *temp = [NSDictionary dictionaryWithObjects:arrayTwo forKeys:arrayOne];
NSArray *sortedArrayOne = [[temp allKeys] sortedArrayUsingSelector:@selector(compare:)];
NSArray *sortedArrayTwo = [temp objectsForKeys:sortedArrayOne notFoundMarker:[NSNull null]];

NSLog(@"%@",sortedArrayOne);
NSLog(@"%@",sortedArrayTwo);

Workflow:
Create dictionary from the arrays -> sort dictionary -> create arrays from dictionary.

EDIT

Use NSSortDescriptor with ascending:NO to sort descending, quick example:

NSDictionary *temp = [NSDictionary dictionaryWithObjects:arrayTwo forKeys:arrayOne];
NSSortDescriptor *theDescriptor = [NSSortDescriptor sortDescriptorWithKey:nil ascending:NO selector:@selector(compare:)];    
NSArray *sortedArrayOne = [[temp allKeys] sortedArrayUsingDescriptors:[NSArray arrayWithObject:theDescriptor]];
NSArray *sortedArrayTwo = [temp objectsForKeys:sortedArrayOne notFoundMarker:[NSNull null]];

edited Aug 10, 2012 at 20:37

answered Aug 10, 2012 at 16:47

Anne

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7 Comments

Lollo Over a year ago

Thanks :) works great :) but is it possible to do the opposite? instead of 1,4,5,7,9 then get it to 9,7,5,4,1 (with names)?

Anne Over a year ago

Added quick example how to sort descending.

Lollo Over a year ago

if i use the number 22, it'll be places between 1 and 4.. how to change that?

Anne Over a year ago

Replace @selector(compare:) by @selector(localizedStandardCompare:).

Lollo Over a year ago

Sry for all this.. but: if i use the number 22, it'll be places between 1 and 4.. how can I change that??

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Ariel · Accepted Answer · 2012-08-10 17:01:39Z

Why don't you just create some new object let's say Player with ivars name and score and store instances of that class in array. Then you'll be able to sort that array as you want for any point in your code like so:

NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"name" ascending:YES] ;
NSArray *sortDescriptors = [NSArray arrayWithObject:sortDescriptor];
NSArray *sortedByName = [players sortedArrayUsingDescriptors:sortDescriptors];

or by score:

NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"score" ascending:NO] ;
NSArray *sortDescriptors = [NSArray arrayWithObject:sortDescriptor];
NSArray *sortedByName = [players sortedArrayUsingDescriptors:sortDescriptors];

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